Question

Determine the molality of a solution containing 1.325g anhydrous Na2Co3 dissolved in 250g water

Answer 1

Answer:

0.05 mol/kg

Explanation:

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Answer 2

Concept:

The term molality is defined as the "total moles of a solute contained in a kilogram of a solvent". Molal concentration is another name for molality. It is a measurement of a solute concentration in a solution.

Given:

The mass of anhydrous Na₂CO₃ = 1.325 g

The mass of the weight = 250 g = 250/1000 Kg = 0.250 Kg

Find:

Determine the molality of a solution containing 1.325g anhydrous Na₂CO₃ dissolved in 250g of water.

Solution:

We know that the molality of a solution can be expressed as:

                       Molality = Moles of solute / Mass of solvent in Kg

The moles of a substance can be calculated as:

                          Moles = Mass / Molar mass

The molar mass of Na₂CO₃ = 106 g/mol

The number of moles of Na₂CO₃ = 1.325 g / 106 g/mol

                                                       = 0.0125 mol

Therefore, the molality of the solution of Na₂CO₃  can be calculated as follows below:

                                         Molality = 0.0125 mol / 0.250 Kg

                                                       = 0.05 mol/Kg

Hence, the molality of a solution containing 1.325g of anhydrous Na₂CO₃ dissolved in 250 g of water is 0.05 mol/Kg.

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