Question

Determine the molar mass of a gas which diffuse four times faster as compared to SO2 gas.

Answer 1

Answer:

this is the answer for this question

Answer 2

The molar mass of a gas which diffuses four times faster as compared to SO2 gas is 4.

• Diffusion is the movement of particles from high concentration to low concentration.
• Diffusion is inversely proportional to the square root of molecular mass.
• Let the molecular mass of unknown gas be x.
• Now,
• $\frac{r1}{r2} = \sqrt{ \frac{64}{x} }$
• Here, r1 is the rate of diffusion of the first gas and r2 is the rate of diffusion of SO2.
• The molecular weight of SO2 is 64g.
• Now putting value in the above formula we get,
• $\frac{4 \: \times r1}{r1} = \sqrt{ \frac{64}{x} }$
• ${4}^{2} = \sqrt{ \frac{64}{x} }$
• $16 = \frac{64}{x}$
• $x = \frac{64}{16} = 4$
• The molar mass of gas which diffuses 4 times faster than SO2 is 4.

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