Question

determine the molarity of a solution formed by dissolving 4.0 gram of NaOH in 250 ml of solution.???​

Answer 1

Answer:

Molarity  (M) = No. of moles of solute/Volume of solution in litres  No. of moles= mass of NaOH / molar mass of NaOH                        = 4g / 40g                       = 0.1 molecular

Volume = 250 / 1000Lit               = 0.250L

M= 0.1 mol/ 0.250L    = 0.4M

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Answer 2

Answer:

Molarity  (M) = No. of moles of solute/Volume of solution in litres  No. of moles= mass of NaOH / molar mass of NaOH                        = 4g / 40g                       = 0.1 molecular

Molarity  (M) = No. of moles of solute/Volume of solution in litres  No. of moles= mass of NaOH / molar mass of NaOH                        = 4g / 40g                       = 0.1 molecularVolume = 250 / 1000Lit               = 0.250L

Molarity  (M) = No. of moles of solute/Volume of solution in litres  No. of moles= mass of NaOH / molar mass of NaOH                        = 4g / 40g                       = 0.1 molecularVolume = 250 / 1000Lit               = 0.250LM= 0.1 mol/ 0.250L    = 0.4M

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