Question

determine the molarity of hcl solution with the help of supplied m/20 naoh solution by titration method

Answer 1

Explanation:

NaOH + HCl -> NaCl + H2O

Since it is one mole of HCl react with one mole of NaOH, you can simplify the equation as :

M1 x V1 = M2 x V2

M1 = Molarity of HCl

V1 = Titration volume of HCl

M2 = Molarity of NaOH

V2 = Volume of NaOH used

Example:

20ml of 0.1M HCl was used to neutralize 50ml NaOH solution during titration.

20 x 0.1 = M2 x 50

M2 = 0.04 M

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Answer 2

Concept:

The number of moles of solute present in a certain number of liters of the solution, or moles per liter of a solution, is known as molar concentration or molarity.

Given:

Molarity of NaOH solution (M₂) = m/20 = 0.05 M

The volume of NaOH solution (V₂) = 20 L

Find:

Determine the molarity of HCl solution with the help of supplied m/20 NaOH solution by titration method.

Solution:

We know that the molarity equation by using titration method can be expressed as:

                                 M₁V₁ = M₂V₂

                            (HCl)            (NaOH)

Let's take the volume of HCl (V₁) to be 50 L.

By substituting the given values in the above expression, we can calculate the molarity of the HCl solution.

M₁ * 50 L = 0.05 M * 20 L

M₁ = (0.05 M * 20 L) / 50 L

M₁ = (1 / 50) M

M₁ = 0.02 M

Hence, the molarity (M₁) of the HCl solution is 0.02 M.

The molarity of HCl solution with the help of supplied m/20 NaOH solution by titration method is 0.02 M.

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