determine the molecular formula of an oxide of iron in which the mass percent of iron and oxygen are 69.9and30.1resp.given that the molar mass of the oxide is 159.69g/mol
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oxygen mass percent = 69.9 + 30.1 = 100.0
mass = 159.69gram/ MOL.
= 159.69/100.0 = 1.5969.
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