Determine the molecular formula of the compound with an empirical formula of CH and a molar mass of 65.09 g/mol.
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empirical formula mass=12+1=13 g/mol
n=molecular mass /empirical formula mass
n=65.09/13=5.006=5 (rounding off)
molecular formula =n(empirical formula)
=5(CH)=C5H5
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