Determine the moment of inertia of the wheel about an axis
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Yeah.. So.. I'm considering the wheel to be a ring (orientation of mass)
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What is the moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel? ... Thus the total moment of inertia of the wheel is I = M r + 8 3 M r = M + 8 3 M ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ r = 1.33 kg + 8 3 (0.220 kg) ⎡ ⎣ ⎢ ⎤ ⎦ ⎥ (0.300 m) = 0.173 kg ⋅ m .
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