Question

determine the natural of the root of the quadratic equation 2x²-3x-4=0
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Answer 1

Answer:

Real and Unequal........

Answer 2

Explanation:

$2 {x}^{2} - 3x - 4 = 0$

$a = 2 \: \: \: \: b = - 3 \: \: \: c = - 4$

${b}^{2} - 4ac$

$9 - 4 \times 2 \times - 4$

$9 + 32$

$41$

$x = \frac{ 3 + \sqrt{41} }{2 \times 2} = \frac{3 + \sqrt{41} }{4}$

$x = \frac{ 3 - \sqrt{41} }{2 \times 2} = \frac{3 - \sqrt{41} }{4}$

that's your answer