Question

determine the nature of root of following equations from their discriminants :- x square -2 x+9/4=0
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Answer 1

Step-by-step explanation:

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hope u understand

Answer 2

Given :-

• Quadratic equation: x² - 2x + 9/4 = 0

To Find :-

• The nature of roots.

Solution :-

Given that, x² - 2x + 9/4 = 0

On comparing with ax² + bx + c = 0 , We get :

➡ a = 1 , b = -2 , c = 9/4

As we know that,

$\huge \mathfrak \red{Δ = b² - 4ac}$

[ Putting values ]

➡ Δ = (-2)² - 4 × 1 × (9/4)

➡ Δ = 4 - 4 × 9/4

➡ Δ = 4 - 9

➡ Δ = -5

$\huge\mathfrak \blue{Δ < 0}$

Hence,

• The roots are not real and unequal.