Question

determine the nature of root of given quadratic equation x^-4x+4=0​

Answer 1

Step-by-step explanation:

x²-4x+4=0

x(x-4)+4=0

x=4 and x=-4

real and distinct OK friend

Answer 2

Answer:

here a = 1, b = - 4 ,c = 4

D = bsq. - 4ac

= (-4)(-4) - 4 × 1 × 4

= 16 - 16 = 0

=》D = 0

Therefore given quadratic equation has two real and equal roots