Question

determine the nature of root of quadratic equation xsq -4x+ 4 =0 ​

Answer 1

Answer:

given , quadratic equation is

x² - 4x + 4 = 0

,

discriminant , D = b² -4ac

= 4² - 4*1*4

= 16 - 16

= 0 .

since,

D = 0

so, roota are real and equal.