determine the nature of root of quadratic equations √3x2+2√3x+√3=0
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Step-by-step explanation:
Given: ★ √3x² +2√3x+√3.
To Find: ★ The nature of its roots.
Concept Used: ★ We will find the discriminant.
Answer: Here D = b²-4ac . => D = (2√3)²-4×√3×√3. => D =12 -12. . °. D =0.
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