Question

determine the nature of root of the given quadratic equation
$= \sqrt{3x { }^{2} } + 2 \sqrt{3} x + \sqrt{3} = 0$
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Answer 1

Answer:

Nature is given by determinant(D) which is equal to b²-4ac

• If D>0, roots are real and distinct
• If D=0, roots are equal
• If D<0, roots does not exist

a = √3

b = 2√3

c = √3

b²-4ac = (2√3)² - 4(√3)(√3)

= 12 - 12

= 0

Therefore, the equation has 2 real and equal roots

Hope it helps......