Determine the nature of roots.a)9a2b2x2–24 abcdx + 16c2d2 = 0 (a ≠ 0, b ≠ 0) b) (x -2a) (x –2b) = 4ab
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Answer:
1st part in photo
2nd:- x2- 2bx -2ax + 4ab = 4ab
so x2- 2bx- 2ax = 0 so no root possible
PLS MARK BRAINLIEST
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