Question

Determine
the nature of roots
For
each of the
Following eq
x²-2x+1=0
​

Answer 1

Answer:

Step-by-step explanation:

x^2 - x - x +1

x(x-1)*-1(x-1)  =0

(x-1)(x-1)=0

x= 1,1

thank you

Answer 2

Answer:

solution

given quadratic equation x^2 - 2x + 1 =0

if discernment D = b^2 - 4ac = 0 real equal roots

D > 0, real district roots

D < 0, no real roots

now in the given equation

a = 1 , b = -2 and c = 1

therefore D = (-2)^2 - 4(1)(1)

=> D = 4 - 4 = 0

roots are real and equal roots