Determine the nature of roots of 2x² + x - 1 = 0.
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Determine the nature of roots of 2x² + x - 1= 0.
Good question,
Here is your answer!
Here a = 2,
b= 1
& c = - 1.
D (discriminant) = b² - 4ac
= 1 - 4*2*-1
= 1 + 8
= 9.
Since D>0,
Hence roots are real & distinct.
= 2x² + 2x - x - 1
= 2x(x+1) - 1(x +1) = 0
=) (2x-1)(x+1) = 0
Hence roots are 1 & 1/2.
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