Question

determine the nature of roots of equation x square -6x+9=0​

Answer 1

Answer:

as fond the discriminant of the equation then you can conclude whether the have different roots ,equal roots or complex in the above equation the roots are equal and they are 3 ,3

use this -b+-root upon b^2-4ac/2a

Answer 2

Answer:

Real and equal

Step-by-step explanation:

Given equation is x²-6x+9=0

here, a=1, b=-6, c=9

to find nature of the roots

Δ = b²-4ac

⇒Δ = (-6)²-4(1)(9)

⇒Δ = 36-4(9)

⇒Δ = 36-36

⇒Δ = 0

Δ=0 represents that roots of the equation are real & equal

∴The nature of the roots of the equation x²-6x+9=0 is real & equal.

HOPE THIS WOULD BE HELPFUL FOR YOU