Question

determine the nature of roots of equation x2- 3x+1 = 0​

Answer 1

Answer:

real and different roots

Answer 2

Answer:

Hope it helps you, Mark as brainilest please

Step-by-step explanation:

Quadratic equation is

=>x^2x

2

-3x-1=0

ANSWER

Now to solve a quadratic equation we can use 3 methods =>

1)Completing the Square Method,

2)Middle term Split method, and

3)By Quadratic formula.

Here we will be using the quadratic formula method --->

d=b^2b

2

- 4×a ×c

=>d = (-3)^2(−3)

2

- {4 × 1×(-1)}

=>d = 9 + 4

=>d = 13.

Since d>0

hence the equation has 2 real and distinct roots.

Hence,

x = \dfrac{-b\pm \sqrt{d}}{2\times{a}}

2×a

−b±

d

=>x = \dfrac{3\pm\sqrt{13}}{2\times{1}}

2×1

3±

13

So, we get=>

Either

x= \dfrac{3 + \sqrt{13}}{2}

2

3+

13

or

x = \dfrac{3 - \sqrt{13}}{2}

2

3−

13

REMEMBER

Remember

In quadratic formula

X = \dfrac{-b\pm\sqrt{d}}{2\times{a}}X=

2×a

−b±

d

and

d is discriminant which determines the nature of roots