Question

determine the Nature of roots of given quadratic
equation X² - 4x + 4 = 0
​

Answer 1

Answer:

The roots are real and equal.

Step-by-step explanation:

Comparing x^2 -4x + 4 = 0 with ax^2 + bx + c = 0, we get

a = 1, b = -4, c=  4

Now, D = b^2 - 4ac = (-4)^2 - 4.1.4 = 16 - 16 = 0

So, D = 0

Therefore, the roots are real and equal.