Question

Determine the nature of roots of the following equation from its discriminant 6p^2 + 6p - 2 = 0 ​

Answer 1

Answer:

6p^2 + 6p - 2 = 0

Here a= 6 b= 6 c= - 2

discriminate b^2-4ac

If b^2-4ac > 0 it will be real and not equal

If b^2-4ac = 0 it will be real and equal

If b^2-4ac < 0 it will be imaginary and not equal

Now put the values of a, b, c

6^2-4(6)(-2)

36+48

84 > 0 so it will be real and not equal