Question

determine the nature of roots of the quadratic equation. 2x^2-5x+7=0​

Answer 1

Step-by-step explanation:

The give equation is

2x2+5x−7=0

By factoring method,

2x2+5x−7=0

(2x+7)(x−1)=0

by the zero property

2x+7=0

and

x−1=0

it followsthe roots are

x=−72 and x=1

Answer 2

Answer:the roots are real and equal

Step-by-step explanation:$2x^{2} -5x+7=0$

comparing the equation in ax^2+bx+c=0

a=2

b=-5

c=7

Delta =b^2-4ac

         =25-4 x 2 x 7

         =25-56

         =   -31

the answer is in negative so

the roots are real and equal.