Question

Determine the nature of roots of the quadratic equation 3x²-7x+4=0

Answer 1

Answer

x1 = 4/3

x2 =1

Explanation

3x^2-7x+4=0

x=(-b±√b^2-4ac)/2a

x=(7±√(-7)^2-4×3×4)/2×3

x=(7±√49-48)/6

x=(7±1)/6

So,

x1 = (7+1)/6 x2 = (7-1)/6

x1 = 4/3 x2 = 1