Determine the nature of roots of the quadratic
equation x2-4x+4=0
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Answer:
the roots are real and equal.
Step-by-step explanation:
x^2-4x+4=0
comparing the above equation with ax^2+bx+c=0
therefore, a=1,b= -4,c=4
b^2-4ac= (-4)^2 - 4(1)(4)
=16-16
=0
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