Question

determine the nature of roots of x square + 2 root 3 x minus 1 is equal to zero​

Answer 1

Answer

Step-by-step explanation:

3x²-4√3x+4=0

to decide nature of roots,

first of all calculate discriminate(D)

D=b²-4×a×c

D=(-4√3)²-4×3×4

D=48-48

=0

∴D=0

hence,roots are real