Question

Determine the nature of roots x2 - 2x+ 1 = 0​

Answer 1

Answer:

${x}^{2} - 2x + 1 = 0 \\ \\ {x}^{2} - 1x - 1x + 1 = 0 \\ \\ x(x - 1) - 1(x - 1) = 0 \\ \\ ( x - 1)(x - 1) \\ \\ x - 1 = 0 \\ \\ x = 1 \\ \\ x - 1 = 0 \\ \\ x = 1 \\ \\ i \: hope \: help \: u \: dear$

Answer 2

Answer:

1x²- 2x + 1 = 0

let us consider 1 as a, 2 as b, 1 (at last) as c

nature of the roots can be determined by the formula b²- 4ac

then,

1² - 4x 1 x 1

=>1 - 4 = -3

therefore, b²- 4ac < 0

the above eq has no real roots.