Question

determine the nature of the image (LOST) using the ray diagram

concave mirror:

object height: 3cm

object distance: 8cm

radius: 6cm

Answer 1

Answer:

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Answer 2

virtual and erect

Explanation:

Given,  

Radius of curvature, R = 6cm

Object distance, u = 8cm

Object height, ho = 3cm

Focal length = -R/2 = -6/2 = -3cm

By using mirror equation,

1/v + 1/u = 1/f

⟹ 1/v = -1/3 - 1/8

⟹ 1/v = (-8 - 3)/24

⟹ 1/v = -11/24

⟹ v = -24/11 or -2 $\frac{2}{11\\}$

Magnification = -v/u = -(-24/11)/8 = 3/11

Hence, the image is virtual and erect.