Question

determine the nature of the root of the following quadratic equation (x+1) (x-2) +x=0​

Answer 1

Answer:

Root of equation

Step-by-step explanation:

(x+1) (x-2) + x = 0

$x^{2} - x -2 + x = 0$

$x^{2} -2 = 0\\x^{2} = 2\\x =+2 or -2$