Question

determine the nature of the root of the following quadratic equation
x²-4x +4 =0​

Answer 1

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Comparing equation

$x²-4x +4 =0$

with STANDARD FORM

$ax²+bc+c=0$

$a=1 ,b= 4 ,c= 4$

we know that

$∆=b²-4 ac$

$= { {(4)}^{2} - 4 \times (1) \times (4)}$

$= 16 - 16 = 0$

Here

$∆= 0$

The roots are real and equal

Answer 2

The nature of the roots are real and equal because the discriminant is zero...!

Hope this helps you❤️✌️