Math, asked by krishnaveni012, 5 hours ago

Determine the nature of the roots for the following quadratic equations: 2x²+5√3x+6=0

Answers

Answered by LivetoLearn143
0

\large\underline{\sf{Solution-}}

Given quadratic equation is

\rm :\longmapsto\: {2x}^{2} + 5 \sqrt{3}x + 6 = 0

We know,

Nature of roots depends upon the Discriminant of quadratic equation.

Let us consider a quadratic equation ax² + bx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D).

If Discriminant, D > 0, then roots of the equation are real and unequal.

If Discriminant, D = 0, then roots of the equation are real and equal.

If Discriminant, D < 0, then roots of the equation are unreal or complex or imaginary.

Where,

Discriminant, D = b² - 4ac

Here,

\rm :\longmapsto\:a = 2

\rm :\longmapsto\:b = 5 \sqrt{3}

\rm :\longmapsto\: c= 6

So,

\rm :\longmapsto\:Discriminant,  D =  {b}^{2} - 4ac

\rm \:  =  \:  \:  {(5 \sqrt{3}) }^{2}  - 4 \times 2 \times 6

\rm \:  =  \:  \: 75 - 48

\rm \:  =  \:  \: 27

\bf\implies \:Discriminant,  D = 27 &gt; 0

Hence,

Roots of the quadratic equation are real and unequal.

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