Question

Determine the nature of the roots for the quadratic equation
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Answer 1

Step-by-step explanation:

The given quadratic equation is

$\sqrt{3} { x }^{2} + \sqrt{2} x - 2 \sqrt{3} = 0$

Here,

$a = \sqrt{3} > 0$

And, discriminant ,

$d = {( \sqrt{2} )}^{2} - 4 \times 2 \sqrt{3} \times \sqrt{3}$

$= 2 - 24 = - 2$

so, the given quadratic equation is positive because its a > 0 and D < 0