Math, asked by thakursangita2002, 4 months ago

Determine the nature of the roots for the quadratic equation
√3x² + √2x - 2√3 = 0.​

Answers

Answered by s13397adisha2258
8

Answer:

The given quadratic equation have two distinct real root.

Step-by-step explanation:

The given quadratic equation is

\sqrt{3}x^2+\sqrt{2}x-2\sqrt{3}=0

3

x

2

+

2

x−2

3

=0

A quadratic equation is ax^2+bx+c=0ax

2

+bx+c=0 .

If b^2-4ac < 0b

2

−4ac<0 , then the equation have two complex roots.

If b^2-4ac=0b

2

−4ac=0 , then the equation have equal real roots.

If b^2-4ac > 0b

2

−4ac>0 , then the equation have two distinct real roots.

In the given equation,

a=\sqrt{3},b=\sqrt{2},c=-2\sqrt{3}a=

3

,b=

2

,c=−2

3

b^2-4ac=(\sqrt{2})^2-4(\sqrt{3})(-2\sqrt{3})=2+24=26b

2

−4ac=(

2

)

2

−4(

3

)(−2

3

)=2+24=26

Since b^2-4ac > 0b

2

−4ac>0 , therefore, the given quadratic equation have two distinct real root.

#Learn more

Determine the nature of the roots of the equation

Step-by-step explanation:

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RATHIJAAT: hi
Answered by afi968119
1

Answer:

Determine the nature of the roots for the quadratic equation

√3x² + √2x - 2√3 = 0 all right

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