Question

determine the nature of the roots for X2-2x+9 upon 4 =0​

Answer 1

Answer:

Roots are real and equal

Step-by-step explanation:

(x²-2x+9)/4 =0

a=1/4     b=-1/2    c=9/4

x=-b±(√b²-4ac)/2a

  x=1     x=1

Answer 2

Answer:

imaginary

Step-by-step explanation:

in order to find nature of roots, we have to find the discriminant which is equal to $b^{2}$-4ac

and if $b^{2}$-4ac is negative, then the roots of the equation are imaginary

(∵ roots of a quadratic equation= -b±$\sqrt{Discriminant}$/2a, so if D is negative then its square root would be imaginary)

and discriminant of the given equation is $2^{2}$-4*1*9=4-36=-32, which is negative.

so the nature of the roots would be imaginary