Question

Determine the nature of the roots of 3x²-2x+6=0?​

Answer 1

Answer:

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The nature of roots= no real roots

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Step-by-step explanation:

$3x²-2x+6=0 \\ \\ compare \: it \: with \: \: \: \: a {x}^{2} + bx + c = 0 \\ \\ we \: have \: \: \: a = 3 \: \: b = - 2 \: \: c = 6 \\ \\ now \: \: {b}^{2} - 4ac = {( - 2)}^{2} - 4 \times 3 \times 6 \\ \\ {b}^{2} - 4ac = 4 - 72 \\ \\ {b}^{2} - 4ac = - 68 \\ \\ {b}^{2} - 4ac < 0 \\ \\ no \: real \: roots \: exists \\ \\ this \: is \: ur \: required \: answer \: :):):):):)$