Determine the nature of the roots of
equation: x2 + 2 root 3x -1 = 0
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Here is your answer :
D = b² - 4ac
D = (2√3)² - 4 (1) (-1)
D = 12 + 4
D = 16
D > 0
So the equation has real and distinct roots.
Vaish720:
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