Question

Determine the nature of the roots of the following quadratic equations from their discriminant: 3y^2+9y+=0​

Answer 1

Answer:

D= b²-4ac

= 9²-4×3×0

= 81

When discriminant is greater than zero, the roots are unequal and real

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Answer 2

Answer:

real and distinct and irrational.

Step-by-step explanation:

Comparing the given equation with  $ax^{2}+bx+c=0$ ;

a = 3 ; b = 9 ; c = 4 ; x = y .

Therefore, discriminant , $D={b^{2}-4ac}$

                                              = 81-48 = 33>0.   (not a perfect square.)

Hence, the roots are real and distinct and irrational.