Determine the nature of the roots of the following quadratic equation (x-1)(2x-5)=0
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hey mate here is your answer : b²–4ac>0
Step-by-step explanation:
x (2x–5) – 1 (2x–5) = 0
2x²–5x–2x + 5 = 0
2x² – 7x + 5 = 0
a = 2, b = –7, c = 5
d = b²– 4ac
(–7) – 4 (2) (5)
=> 49 – 40
=> 9
=> b²–4ac > 0
hence, it is real and distinct!!
I HOPE IT WILL HELPS YOU!!!
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