Question

Determine the nature of the roots of the following quadratic equation (x-1)(2x-5)=0​

Answer 1

Answer:

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Answer 2

Answer:

hey mate here is your answer : b²–4ac>0

Step-by-step explanation:

x (2x–5) – 1 (2x–5) = 0

2x²–5x–2x + 5 = 0

2x² – 7x + 5 = 0

a = 2, b = –7, c = 5

d = b²– 4ac

(–7) – 4 (2) (5)

=> 49 – 40

=> 9

=> b²–4ac > 0

hence, it is real and distinct!!

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