Determine the nature of the roots of
the given quadratic equation.
Y2+2y+9 = 0
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Answer:
Step-by-step explanation:
y²+2y+9 = 0
here a=1 ,b=2, c=9
So discriminant=b²-4ac
=4-4*1*9=4-36=-32
Thus the roots are imaginary and unequal
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