Question

determine the nature of the roots of the quadratic equation 3x^2 -4√3x+4=0​

Answer 1

Answer:  Real and Equal

Step-by-step explanation:

$3x^{2} - 4\sqrt{3} x + 4 = 0$

To determine the nature of the roots, we must check it's discriminant.

=>  Discriminant (D) = $b^{2} -4ac$    

Here  $a = 3$,  $b = -4\sqrt{3}$  and  $c = 4$

=> $D = (-4\sqrt{3})^{2} - 4 (3) (4)$

=>  $D = 48 - 48 = 0$

=>  Since D = 0, the nature of the roots of this quadratic equation is real and equal

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