Question

Determine the nature of the roots of the quadratic equation 2x² - 3X -4 = 0 from their
discriminant (∆).​

Answer 1

Answer:

$d = {b}^{2} - 4ac \\ = ( { - 3}^{2}) - 4 \times 2 \times - 4 \\ = 9 + 32 \\ = 41 \\ d < 41 \\ hence \: the \: two\: distinct \: and \: real \: root$

Answer 2

2x²-3x-4=0

compare equation with ax²+bx+c=0

a=2, b=-3, c=-4

b²-4ac= (-3)²-4×2×(-4)

=9+32

=41

b²-4ac is greater than 0

therefore, the roots of quadratic equation is real and equal.