Question

determine the nature of the roots of the quadratic equation 4xsqr-4x +1 =0​

Answer 1

Step-by-step explanation:

4x²-4x + 1 = 0

x = [-b± √b²-4ac]/2a

= -(-4) ± √4² -4(4)(1) / 2(4)

x =[ 4± (√ 16-16)] / 8

x =( 4±√0) /8

x = 1/2