Question

determine the nature of the roots (x-1)(2x-7)=0 please help ​

Answer 1

==> (x - 1)(2x - 7) = 0

==> 2x² - 7x - 2x + 7 = 0

==> 2x² - 9x + 7 = 0

On comparing this Equation with the standard form of quadratic equation ( i.e., ax² + bx + c = 0 ) , We get

a = 2 , b = -9 , c = 7

Now,

Discriminant, D = b² - 4ac

==> (-9)² - 4×2×7

==> 81 - 56

==> 25

Here the discriminant is greater than zero, So the roots of this quadratic equation will be real and distinct.