Question

determine the nature roots √3x^+2√3x+√3=0
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Answer 1

Given:

★√3x² +2√3x+√3.

To Find:

★The nature of its roots.

Concept Used:

★We will find the discriminant.

Answer:

Here D = b²-4ac .

=> D = (2√3)²-4×√3×√3.

=> D =12 -12

.°. D =0.

Therefore it has real roots which are equal.