Question

Determine the nature roots for x2 -6x+9=0.

A. 9

B. 2

C. 6

D. None of the above​

Answer 1

Answer:

Answer is option d) None of these.

Step-by-step explanation:

Nature of the roots=b^2-4ac.

Her, a= 1, b=6, c=9. (Take one coefficients of the question.)

substitute in b^2-4ac ,

6^2-4x1x9 = 36-36 =0.

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Answer 2

Step-by-step explanation:

First we calculate discriminant of this quadratic equation to check the nature of roots.

Use discriminant formula with a=1, b=6, c=9

Discriminant D = b^2 - 4ac

D = 6^2 - 4 x 1 x 9

D = 36 - 36

D = 0

Since discriminant = b^2 - 4ac = 0, which is zero, hence both roots of this equation are equal.

Roots(α, β) = −b ± √ b^2/2a − 4ac

Root = α = β = −6 ± √0/ 2x1

Root = α = β = -6/2

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