Question

Determine the net force required to accelerate a 540 kg ultralight car from 0 to 27m/s in 10.0 seconds.​

Answer 1

Answer:

ig 2.7 *540 = 1458N

Explanation:

coz acceleration =v-u/t

=27-0/10

which will be 2.7 with the unit kg m/s or N

and then F = m*a

=540*2.7 with the unit m/s^2 * kg which can be written as N

is it correct??

Answer 2

Given,

Mass of the car = 540 kg

Speed = 27 m/s

Time = 10.0 seconds

To Find,

The net force =?

Solution,

We can solve the question using the following steps:

We know,

$F = ma$       -------------- (1)

Here, $F =$ Force

          $m =$ Mass

           $a =$ Acceleration

Now,

To find acceleration we use the first equation of motion,

$v = u + at$   ------------- (2)

It is given that

$v = 27m/s, u = 0m/s, t = 10s$

Substituting the values in equation (2),

$27 = 0 + a*10$

$27 = 10a$

$a = \frac{27}{10} = 2.7m/s^{2}$

Now, substituting all the values in equation (1),

$F = 540*2.7$

$F = 1,458 N$

Hence, the net force is equal to 1,458 N.