Math, asked by Powermania5501, 1 year ago

Determine the no. nearest to 110000 but greater than 100000 which is exactly divisible by 8,15 and 21.

Answers

Answered by Shivsm
3
The number which is divisible by 8, 15, and 21 is also divisible by the L.C.M of the number 8, 15 and 21. The L. C. M of 8, 15, and 21 is calculates as:
= LCM of 8,15 and 21=840

=11000 can be divided by 840 =800

Thus, the number less than 110000 and nearest to 110000 that is divisible by 840 is 110000 – 800 = 109200

Now, 109200 is also greater than 100000.

Thus, the number nearest to 110000 and greater than 100000 which is exactly divisible by 8, 15, and 21 is 109200


Answered by mahabir1234asansol
0

Answer:

yyoodihpoyyyykgxggyogcgoxhl

Similar questions