Question

determine the no of atoms in 5.40 grams of boron

Answer 1

One mole of Boron is equals to 6.022 * 10 to the power 23 atoms so 5.40 gram of Boron is equals to 3 *10 to the power 23 atoms

Answer 2

Answer:

There are approximately 3.00 x $10^{23$ atoms in 5.40 grams of boron.

Explanation:

From the above question,

To determine the molar mass of boron. The molar mass of boron is 10.81 g/mol, which is the mass of one mole of boron atoms.

To calculate the number of moles of boron in 5.40 grams.

This can be done using the formula:

moles = mass / molar mass

moles = 5.40 g / 10.81 g/mol

moles =  0.499 moles

Use Avogadro's number to calculate the number of atoms in 0.499 moles of boron. Avogadro's number is 6.022 x $10^{23$ atoms/mol.

number of atoms = moles x Avogadro's number

number of atoms = 0.499 mol x 6.022 x $10^{23$ atoms/mol

number of atoms = 3.00 x $10^{23$ atoms

Therefore,

          There are approximately 3.00 x $10^{23$ atoms in 5.40 grams of boron.

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