Chemistry, asked by kavitaprasad108, 1 year ago

Determine the normality of the given HCL solution by titrating again N/20 Na2Co3 solution

Answers

Answered by Anonymous
2

Answer:

Explanation:

The strength of hydrochloric acid is determined by its titration against the standard solution of sodium carbonate. The reaction that takes place is -

Na2CO3 + 2HCl ⎯→ 2 NaCl + CO2 + H2O

In the process methyl orange, a weak base is used as an indicator. The proton furnished by the addition of the acid that first neutralises the sodium carbonate solution. When the entire solution of sodium carbonate is neutralised, the last drop of the acid that is added from the burette produces the red colour change, which is the end point. The concentration (strength) of the unknown solution is calculated in g/L. It is calculated from the molarity of the solution. Thus, molarity -

a1M1V1 = a2M2V2

where, a1 and a2 are the acidity and basicity of the alkali and acid and M1 and M2 are the molarities, V1 and V2 are the volumes of the base and acid used to neutralise each other.

Answered by Anonymous
0

Answer:

Explanation:

The strength of hydrochloric acid is determined by its titration against the standard solution of sodium carbonate. The reaction that takes place is -

Na2CO3 + 2HCl ⎯→ 2 NaCl + CO2 + H2O

In the process methyl orange, a weak base is used as an indicator. The proton furnished by the addition of the acid that first neutralises the sodium carbonate solution. When the entire solution of sodium carbonate is neutralised, the last drop of the acid that is added from the burette produces the red colour change, which is the end point. The concentration (strength) of the unknown solution is calculated in g/L. It is calculated from the molarity of the solution. Thus, molarity -

a1M1V1 = a2M2V2

where, a1 and a2 are the acidity and basicity of the alkali and acid and M1 and M2 are the molarities, V1 and V2 are the volumes of the base and acid used to neutralise each other.

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