Determine the normality of the given hcl solution by titrating it against n/20na2co3 solution
Answers
Answer ⇒ Normality of HCl in 1 L of solution is N/20.
Explanation ⇒ The Titration of HCl solution with Sodium carbonate is very famous among students of class 11th and 12th.
Procedure ⇒
Its an two step reaction, which is done in form of titartion.
When you add a HCl solution to a solution of sodium carbonate, the hydrogen ion in HCl switches places with one of the sodium ions in Na₂CO₃ to produce sodium hydrogen carbonate, also known as sodium bicarbonate (baking soda), and sodium chloride (salt).
Na₂CO₃(aq) + HCl(aq) ---------⇒ NaHCO₃(aq) + NaCl(aq)
Sodium hydrogen carbonate is basic, and it reacts with the HCl still in solution to produce sodium chloride, carbon dioxide and water.
NaHCO₃(aq) + HCl(aq) -------- NaCl(aq) + CO₂(g) + H₂O(l)
Phenolphthalein is a good indicator for the first reaction because it responds to the pH change caused by the formation of sodium hydrogen carbonate.
Generally, It is pink in basic solutions and turns colorless as soon as the solution becomes acidic.
Methyl orange, on the other hand, responds to pH changes associated with the formation of NaCl, changing from yellow to red as the solution becomes more acidic. At neutrality, it is a distinct orange color.
Calculations ⇒
Now, If you wanted to determine the Normality, then we need to follow small procedure of calculations.
Normality of Na₂CO₃ is N/20. This means, no. of gram equivalents of HCl in 1 Liter of solution is 1/20.
∴ no. of gm. equivalent = 1/20
∴ no. of moles × 2 = 1/20
∴ no. of moles = 1/40
From the two reaction, it is clear that, 2 moles of HCl reacts with 1 mole of sodium carbonate.
∴ 1/40 moles of sodium carbonate reacts with 1/20 moles of HCl.
∴ no. of gram equivalent of HCl = no. of moles × 1
∴ no. of gm. equivalent = 1/20 gequiv.
∴ Normality of HCl in 1 L of solution is N/20.
Hope it helps.
Answer:Now, If you wanted to determine the Normality, then we need to follow small procedure of calculations.
Normality of Na₂CO₃ is N/20. This means, no. of gram equivalents of HCl in 1 Liter of solution is 1/20.
∴ no. of gm. equivalent = 1/20
∴ no. of moles × 2 = 1/20
∴ no. of moles = 1/40
From the two reaction, it is clear that, 2 moles of HCl reacts with 1 mole of sodium carbonate.
∴ 1/40 moles of sodium carbonate reacts with 1/20 moles of HCl.
∴ no. of gram equivalent of HCl = no. of moles × 1
∴ no. of gm. equivalent = 1/20 gequiv.
∴ Normality of HCl in 1 L of solution is N/20.