Determine the number nearest to 100000 but greater than 100000 which is exactly divisible by each of 8 15 and 21
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Answered by
15
Answer:
100800
Step-by-step explanation:
take LCM of 8,15,21 which is 840
now devide 100000 by 840 you get remainder 40
now to get the number which is devisible by 8,15,21
you have to 100000+840-40=100800
Answered by
4
Step-by-step explanation:
take the lcm of 8 15 and 21 which is 840 then dive 840 from 1lakh we will get 40 as remainder then add 100000with 840 then subtract 40 we will get 100800
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