Math, asked by vulcandynamite53441, 11 months ago

Determine the number nearest to 100000 but greater than 100000 which is exactly divisible by each of 8 15 and 21

Answers

Answered by krish7653
15

Answer:

100800

Step-by-step explanation:

take LCM of 8,15,21 which is 840

now devide 100000 by 840 you get remainder 40

now to get the number which is devisible by 8,15,21

you have to 100000+840-40=100800

Answered by dakshya74
4

Step-by-step explanation:

take the lcm of 8 15 and 21 which is 840 then dive 840 from 1lakh we will get 40 as remainder then add 100000with 840 then subtract 40 we will get 100800

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