Determine the number nearest to 100000 but greater than 10000 which is exactly divisible by each of 8,15and 21
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Answer:
First lcm must be taken for the number 8,15 and 20
Then we get 840
Next divide 100000by840 we get remainder 40
Now we must add 840 to 100000 and subtract 40 to the sum.
So we get,
100000+840-40=100800
This the no.divisible by 8,15 ,20
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